Base | Representation |
---|---|
bin | 10011101101000000111… |
… | …000010110001111010001 |
3 | 11210102220210220211021010 |
4 | 103231000320112033101 |
5 | 134140444310224332 |
6 | 2514004231521133 |
7 | 166552314254016 |
oct | 23550070261721 |
9 | 4712823824233 |
10 | 1354003211217 |
11 | 482258572068 |
12 | 19a4b8b291a9 |
13 | 9a8b33413a7 |
14 | 4976982770d |
15 | 25349e769cc |
hex | 13b40e163d1 |
1354003211217 has 8 divisors (see below), whose sum is σ = 1813433300224. Its totient is φ = 898620964848.
The previous prime is 1354003211213. The next prime is 1354003211237. The reversal of 1354003211217 is 7121123004531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1354003211217 - 22 = 1354003211213 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1354003211213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1011959878 + ... + 1011961215.
It is an arithmetic number, because the mean of its divisors is an integer number (226679162528).
Almost surely, 21354003211217 is an apocalyptic number.
It is an amenable number.
1354003211217 is a deficient number, since it is larger than the sum of its proper divisors (459430089007).
1354003211217 is a wasteful number, since it uses less digits than its factorization.
1354003211217 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2023921319.
The product of its (nonzero) digits is 5040, while the sum is 30.
Adding to 1354003211217 its reverse (7121123004531), we get a palindrome (8475126215748).
The spelling of 1354003211217 in words is "one trillion, three hundred fifty-four billion, three million, two hundred eleven thousand, two hundred seventeen".
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