13540200053 has 4 divisors (see below), whose sum is σ = 13730907168. Its totient is φ = 13349492940.

The previous prime is 13540200043. The next prime is 13540200067. The reversal of 13540200053 is 35000204531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35000204531 = 349 ⋅100287119.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13540200053 is a prime.

It is a super-2 number, since 2×13540200053² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13540200013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95353451 + ... + 95353592.

It is an arithmetic number, because the mean of its divisors is an integer number (3432726792).

Almost surely, 2^13540200053 is an apocalyptic number.

It is an amenable number.

13540200053 is a deficient number, since it is larger than the sum of its proper divisors (190707115).

13540200053 is an equidigital number, since it uses as much as digits as its factorization.

13540200053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190707114.

The product of its (nonzero) digits is 1800, while the sum is 23.

Adding to 13540200053 its reverse (35000204531), we get a palindrome (48540404584).

The spelling of 13540200053 in words is "thirteen billion, five hundred forty million, two hundred thousand, fifty-three".