Search a number
-
+
13540212551 = 239193129339
BaseRepresentation
bin11001001110000111…
…10011111101000111
31021221122022001202202
430213003303331013
5210212243300201
610115325425115
7656352623225
oct144703637507
937848261682
1013540212551
115819108108
12275a70b19b
13137a2962b8
149263cbb15
15543aaec6b
hex3270f3f47

13540212551 has 8 divisors (see below), whose sum is σ = 13604371200. Its totient is φ = 13476116920.

The previous prime is 13540212529. The next prime is 13540212557. The reversal of 13540212551 is 15521204531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13540212551 is a prime.

It is a super-3 number, since 3×135402125513 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13540212557) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 446840 + ... + 476178.

It is an arithmetic number, because the mean of its divisors is an integer number (1700546400).

Almost surely, 213540212551 is an apocalyptic number.

13540212551 is a deficient number, since it is larger than the sum of its proper divisors (64158649).

13540212551 is a wasteful number, since it uses less digits than its factorization.

13540212551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31509.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 13540212551 in words is "thirteen billion, five hundred forty million, two hundred twelve thousand, five hundred fifty-one".

Divisors: 1 239 1931 29339 461509 7012021 56653609 13540212551