13540325413 has 4 divisors (see below), whose sum is σ = 13540885120. Its totient is φ = 13539765708.

The previous prime is 13540325411. The next prime is 13540325473. The reversal of 13540325413 is 31452304531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13540325413 - 2¹ = 13540325411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13540325411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241845 + ... + 292522.

It is an arithmetic number, because the mean of its divisors is an integer number (3385221280).

Almost surely, 2^13540325413 is an apocalyptic number.

It is an amenable number.

13540325413 is a deficient number, since it is larger than the sum of its proper divisors (559707).

13540325413 is an equidigital number, since it uses as much as digits as its factorization.

13540325413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 559706.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13540325413 its reverse (31452304531), we get a palindrome (44992629944).

The spelling of 13540325413 in words is "thirteen billion, five hundred forty million, three hundred twenty-five thousand, four hundred thirteen".