Base | Representation |
---|---|
bin | 1100010100001001101111… |
… | …1101100110101001011011 |
3 | 1202221110000112000012020220 |
4 | 3011002123331212221123 |
5 | 3233321121001101210 |
6 | 44444204052051123 |
7 | 2565154404016611 |
oct | 305023375465133 |
9 | 52843015005226 |
10 | 13540353534555 |
11 | 4350482634a51 |
12 | 1628265003aa3 |
13 | 772b081ab693 |
14 | 34b4dc7636b1 |
15 | 187337d37c70 |
hex | c509bf66a5b |
13540353534555 has 16 divisors (see below), whose sum is σ = 21835152789504. Its totient is φ = 7164659507040.
The previous prime is 13540353534541. The next prime is 13540353534557. The reversal of 13540353534555 is 55543535304531.
It is a happy number.
It is not a de Polignac number, because 13540353534555 - 222 = 13540349340251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13540353534498 and 13540353534507.
It is not an unprimeable number, because it can be changed into a prime (13540353534557) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3553896661 + ... + 3553900470.
It is an arithmetic number, because the mean of its divisors is an integer number (1364697049344).
Almost surely, 213540353534555 is an apocalyptic number.
13540353534555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13540353534555 is a deficient number, since it is larger than the sum of its proper divisors (8294799254949).
13540353534555 is a wasteful number, since it uses less digits than its factorization.
13540353534555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7107797266.
The product of its (nonzero) digits is 20250000, while the sum is 51.
The spelling of 13540353534555 in words is "thirteen trillion, five hundred forty billion, three hundred fifty-three million, five hundred thirty-four thousand, five hundred fifty-five".
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