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135403555233 = 3195344820773
BaseRepresentation
bin111111000011010101…
…1100100100110100001
3110221111111200021220010
41332012223210212201
54204301302231413
6142111544035133
712532266141462
oct1760653444641
9427444607803
10135403555233
1152473860161
12222aa462aa9
13c9cb51acab
1467a6db8d69
1537c7431dc3
hex1f86ae49a1

135403555233 has 16 divisors (see below), whose sum is σ = 193625743680. Its totient is φ = 83904485184.

The previous prime is 135403555109. The next prime is 135403555237. The reversal of 135403555233 is 332555304531.

It is not a de Polignac number, because 135403555233 - 214 = 135403538849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135403555191 and 135403555200.

It is not an unprimeable number, because it can be changed into a prime (135403555237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22407366 + ... + 22413407.

It is an arithmetic number, because the mean of its divisors is an integer number (12101608980).

Almost surely, 2135403555233 is an apocalyptic number.

It is an amenable number.

135403555233 is a deficient number, since it is larger than the sum of its proper divisors (58222188447).

135403555233 is a wasteful number, since it uses less digits than its factorization.

135403555233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44820848.

The product of its (nonzero) digits is 405000, while the sum is 39.

Adding to 135403555233 its reverse (332555304531), we get a palindrome (467958859764).

The spelling of 135403555233 in words is "one hundred thirty-five billion, four hundred three million, five hundred fifty-five thousand, two hundred thirty-three".

Divisors: 1 3 19 53 57 159 1007 3021 44820773 134462319 851594687 2375500969 2554784061 7126502907 45134518411 135403555233