Base | Representation |
---|---|
bin | 1100010100001001111011… |
… | …1110100000101101000010 |
3 | 1202221110011001011101111101 |
4 | 3011002132332200231002 |
5 | 3233321221422312002 |
6 | 44444213100005014 |
7 | 2565155556605446 |
oct | 305023676405502 |
9 | 52843131141441 |
10 | 13540404104002 |
11 | 43504a9134586 |
12 | 1628279b3076a |
13 | 772b15806029 |
14 | 34b505368826 |
15 | 18733c4c6587 |
hex | c509efa0b42 |
13540404104002 has 4 divisors (see below), whose sum is σ = 20310606156006. Its totient is φ = 6770202052000.
The previous prime is 13540404103981. The next prime is 13540404104009. The reversal of 13540404104002 is 20040140404531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9711568762921 + 3828835341081 = 3116339^2 + 1956741^2 .
It is not an unprimeable number, because it can be changed into a prime (13540404104009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3385101025999 + ... + 3385101026002.
Almost surely, 213540404104002 is an apocalyptic number.
13540404104002 is a deficient number, since it is larger than the sum of its proper divisors (6770202052004).
13540404104002 is an equidigital number, since it uses as much as digits as its factorization.
13540404104002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6770202052003.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 13540404104002 its reverse (20040140404531), we get a palindrome (33580544508533).
The spelling of 13540404104002 in words is "thirteen trillion, five hundred forty billion, four hundred four million, one hundred four thousand, two".
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