135404451253 has 4 divisors (see below), whose sum is σ = 137425413280. Its totient is φ = 133383489228.

The previous prime is 135404451211. The next prime is 135404451323. The reversal of 135404451253 is 352154404531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135404451253 - 2¹³ = 135404443061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135404451953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1010480913 + ... + 1010481046.

It is an arithmetic number, because the mean of its divisors is an integer number (34356353320).

Almost surely, 2^135404451253 is an apocalyptic number.

It is an amenable number.

135404451253 is a deficient number, since it is larger than the sum of its proper divisors (2020962027).

135404451253 is an equidigital number, since it uses as much as digits as its factorization.

135404451253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2020962026.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 135404451253 its reverse (352154404531), we get a palindrome (487558855784).

The spelling of 135404451253 in words is "one hundred thirty-five billion, four hundred four million, four hundred fifty-one thousand, two hundred fifty-three".