13540450024034 has 4 divisors (see below), whose sum is σ = 20310675036054. Its totient is φ = 6770225012016.

The previous prime is 13540450023973. The next prime is 13540450024039. The reversal of 13540450024034 is 43042005404531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12636994071025 + 903455953009 = 3554855^2 + 950503^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13540450023985 and 13540450024003.

It is not an unprimeable number, because it can be changed into a prime (13540450024039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3385112506007 + ... + 3385112506010.

Almost surely, 2^{13540450024034} is an apocalyptic number.

13540450024034 is a deficient number, since it is larger than the sum of its proper divisors (6770225012020).

13540450024034 is an equidigital number, since it uses as much as digits as its factorization.

13540450024034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6770225012019.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 13540450024034 its reverse (43042005404531), we get a palindrome (56582455428565).

The spelling of 13540450024034 in words is "thirteen trillion, five hundred forty billion, four hundred fifty million, twenty-four thousand, thirty-four".