Base | Representation |
---|---|
bin | 11001001110001101… |
… | …11110010100100011 |
3 | 1021221200212011210110 |
4 | 30213012332110203 |
5 | 210213001311233 |
6 | 10115355302403 |
7 | 656362644636 |
oct | 144706762443 |
9 | 37850764713 |
10 | 13541041443 |
11 | 5819623946 |
12 | 275aa4aa03 |
13 | 137a4c6677 |
14 | 926565c1d |
15 | 543bc5663 |
hex | 3271be523 |
13541041443 has 8 divisors (see below), whose sum is σ = 18360734400. Its totient is φ = 8874354728.
The previous prime is 13541041439. The next prime is 13541041453. The reversal of 13541041443 is 34414014531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13541041443 - 22 = 13541041439 is a prime.
It is a super-2 number, since 2×135410414432 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13541041443.
It is not an unprimeable number, because it can be changed into a prime (13541041453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38251353 + ... + 38251706.
It is an arithmetic number, because the mean of its divisors is an integer number (2295091800).
Almost surely, 213541041443 is an apocalyptic number.
13541041443 is a deficient number, since it is larger than the sum of its proper divisors (4819692957).
13541041443 is an equidigital number, since it uses as much as digits as its factorization.
13541041443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76503121.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 13541041443 its reverse (34414014531), we get a palindrome (47955055974).
The spelling of 13541041443 in words is "thirteen billion, five hundred forty-one million, forty-one thousand, four hundred forty-three".
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