13541100101 has 4 divisors (see below), whose sum is σ = 14253789600. Its totient is φ = 12828410604.

The previous prime is 13541100091. The next prime is 13541100103. The reversal of 13541100101 is 10100114531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13541100101 - 2¹⁸ = 13540837957 is a prime.

It is a super-2 number, since 2×13541100101² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13541100101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13541100103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356344721 + ... + 356344758.

It is an arithmetic number, because the mean of its divisors is an integer number (3563447400).

Almost surely, 2^13541100101 is an apocalyptic number.

It is an amenable number.

13541100101 is a deficient number, since it is larger than the sum of its proper divisors (712689499).

13541100101 is an equidigital number, since it uses as much as digits as its factorization.

13541100101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 712689498.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 13541100101 its reverse (10100114531), we get a palindrome (23641214632).

The spelling of 13541100101 in words is "thirteen billion, five hundred forty-one million, one hundred thousand, one hundred one".