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135411468383623 = 1090312419652241
BaseRepresentation
bin11110110010011111110000…
…011110001011010110000111
3122202110012200001111000221211
4132302133300132023112013
5120222040141401233443
61155555100401552251
740344104264054455
oct3662376036132607
9582405601430854
10135411468383623
113a167754807483
121322b796945687
135a73328c475a3
142561d42c9d9d5
15109c56a42319d
hex7b27f078b587

135411468383623 has 4 divisors (see below), whose sum is σ = 135423888046768. Its totient is φ = 135399048720480.

The previous prime is 135411468383617. The next prime is 135411468383627. The reversal of 135411468383623 is 326383864114531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135411468383623 - 25 = 135411468383591 is a prime.

It is a super-2 number, since 2×1354114683836232 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135411468383627) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6209815218 + ... + 6209837023.

It is an arithmetic number, because the mean of its divisors is an integer number (33855972011692).

Almost surely, 2135411468383623 is an apocalyptic number.

135411468383623 is a deficient number, since it is larger than the sum of its proper divisors (12419663145).

135411468383623 is a wasteful number, since it uses less digits than its factorization.

135411468383623 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12419663144.

The product of its digits is 29859840, while the sum is 58.

The spelling of 135411468383623 in words is "one hundred thirty-five trillion, four hundred eleven billion, four hundred sixty-eight million, three hundred eighty-three thousand, six hundred twenty-three".

Divisors: 1 10903 12419652241 135411468383623