Base | Representation |
---|---|
bin | 111111000011101000… |
… | …1100011010111000111 |
3 | 110221112012102010111022 |
4 | 1332013101203113013 |
5 | 4204311324332443 |
6 | 142112541301355 |
7 | 12532446600035 |
oct | 1760721432707 |
9 | 427465363438 |
10 | 135413511623 |
11 | 52479440585 |
12 | 222b186485b |
13 | ca005c5a50 |
14 | 67a844b555 |
15 | 37c824be68 |
hex | 1f874635c7 |
135413511623 has 4 divisors (see below), whose sum is σ = 145829935608. Its totient is φ = 124997087640.
The previous prime is 135413511593. The next prime is 135413511647. The reversal of 135413511623 is 326115314531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 326115314531 = 3739 ⋅87219929.
It is a cyclic number.
It is not a de Polignac number, because 135413511623 - 210 = 135413510599 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135413511923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5208211973 + ... + 5208211998.
It is an arithmetic number, because the mean of its divisors is an integer number (36457483902).
Almost surely, 2135413511623 is an apocalyptic number.
135413511623 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
135413511623 is a deficient number, since it is larger than the sum of its proper divisors (10416423985).
135413511623 is a wasteful number, since it uses less digits than its factorization.
135413511623 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10416423984.
The product of its digits is 32400, while the sum is 35.
The spelling of 135413511623 in words is "one hundred thirty-five billion, four hundred thirteen million, five hundred eleven thousand, six hundred twenty-three".
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