Base | Representation |
---|---|
bin | 10011101101001001111… |
… | …001001101110111111101 |
3 | 11210110022100110201222121 |
4 | 103231021321031313331 |
5 | 134141302013342140 |
6 | 2514031233042541 |
7 | 166556131525630 |
oct | 23551171156775 |
9 | 4713270421877 |
10 | 1354154434045 |
11 | 48232596a006 |
12 | 19a53b6b6451 |
13 | 9a90877aa5a |
14 | 4978194dc17 |
15 | 2535839864a |
hex | 13b49e4ddfd |
1354154434045 has 8 divisors (see below), whose sum is σ = 1857126081024. Its totient is φ = 928563040464.
The previous prime is 1354154434021. The next prime is 1354154434051. The reversal of 1354154434045 is 5404344514531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1354154434045 - 213 = 1354154425853 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1354154433992 and 1354154434010.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19345063309 + ... + 19345063378.
It is an arithmetic number, because the mean of its divisors is an integer number (232140760128).
Almost surely, 21354154434045 is an apocalyptic number.
It is an amenable number.
1354154434045 is a deficient number, since it is larger than the sum of its proper divisors (502971646979).
1354154434045 is an equidigital number, since it uses as much as digits as its factorization.
1354154434045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38690126699.
The product of its (nonzero) digits is 1152000, while the sum is 43.
Adding to 1354154434045 its reverse (5404344514531), we get a palindrome (6758498948576).
The spelling of 1354154434045 in words is "one trillion, three hundred fifty-four billion, one hundred fifty-four million, four hundred thirty-four thousand, forty-five".
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