13542134004313 has 4 divisors (see below), whose sum is σ = 13581160327440. Its totient is φ = 13503107681188.

The previous prime is 13542134004271. The next prime is 13542134004319. The reversal of 13542134004313 is 31340043124531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13542134004313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13542134004319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19513161043 + ... + 19513161736.

It is an arithmetic number, because the mean of its divisors is an integer number (3395290081860).

Almost surely, 2^{13542134004313} is an apocalyptic number.

It is an amenable number.

13542134004313 is a deficient number, since it is larger than the sum of its proper divisors (39026323127).

13542134004313 is an equidigital number, since it uses as much as digits as its factorization.

13542134004313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39026323126.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 13542134004313 its reverse (31340043124531), we get a palindrome (44882177128844).

The spelling of 13542134004313 in words is "thirteen trillion, five hundred forty-two billion, one hundred thirty-four million, four thousand, three hundred thirteen".