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13542134203 = 131041702631
BaseRepresentation
bin11001001110010110…
…01001000110111011
31021221202220200210001
430213023021012323
5210213241243303
610115434533431
7656405145553
oct144713110673
937852820701
1013542134203
11581a1aa954
12275b297277
13137a7b9b80
1492676c163
15543d3e31d
hex3272c91bb

13542134203 has 4 divisors (see below), whose sum is σ = 14583836848. Its totient is φ = 12500431560.

The previous prime is 13542134191. The next prime is 13542134231. The reversal of 13542134203 is 30243124531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13542134203 - 213 = 13542126011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13542134503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520851303 + ... + 520851328.

It is an arithmetic number, because the mean of its divisors is an integer number (3645959212).

Almost surely, 213542134203 is an apocalyptic number.

13542134203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13542134203 is a deficient number, since it is larger than the sum of its proper divisors (1041702645).

13542134203 is a wasteful number, since it uses less digits than its factorization.

13542134203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1041702644.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13542134203 its reverse (30243124531), we get a palindrome (43785258734).

The spelling of 13542134203 in words is "thirteen billion, five hundred forty-two million, one hundred thirty-four thousand, two hundred three".

Divisors: 1 13 1041702631 13542134203