Base | Representation |
---|---|
bin | 11001001110010110… |
… | …01101001001010111 |
3 | 1021221202221112110122 |
4 | 30213023031021113 |
5 | 210213242310433 |
6 | 10115435142155 |
7 | 656405245022 |
oct | 144713151127 |
9 | 37852845418 |
10 | 13542150743 |
11 | 581a211320 |
12 | 275b2a495b |
13 | 137a7c4564 |
14 | 9267741b9 |
15 | 543d44198 |
hex | 3272cd257 |
13542150743 has 4 divisors (see below), whose sum is σ = 14773255368. Its totient is φ = 12311046120.
The previous prime is 13542150679. The next prime is 13542150757. The reversal of 13542150743 is 34705124531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13542150743 - 26 = 13542150679 is a prime.
It is a super-2 number, since 2×135421507432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13542150443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615552296 + ... + 615552317.
It is an arithmetic number, because the mean of its divisors is an integer number (3693313842).
Almost surely, 213542150743 is an apocalyptic number.
13542150743 is a deficient number, since it is larger than the sum of its proper divisors (1231104625).
13542150743 is a wasteful number, since it uses less digits than its factorization.
13542150743 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1231104624.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 13542150743 in words is "thirteen billion, five hundred forty-two million, one hundred fifty thousand, seven hundred forty-three".
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