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13542150743 = 111231104613
BaseRepresentation
bin11001001110010110…
…01101001001010111
31021221202221112110122
430213023031021113
5210213242310433
610115435142155
7656405245022
oct144713151127
937852845418
1013542150743
11581a211320
12275b2a495b
13137a7c4564
149267741b9
15543d44198
hex3272cd257

13542150743 has 4 divisors (see below), whose sum is σ = 14773255368. Its totient is φ = 12311046120.

The previous prime is 13542150679. The next prime is 13542150757. The reversal of 13542150743 is 34705124531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13542150743 - 26 = 13542150679 is a prime.

It is a super-2 number, since 2×135421507432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13542150443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615552296 + ... + 615552317.

It is an arithmetic number, because the mean of its divisors is an integer number (3693313842).

Almost surely, 213542150743 is an apocalyptic number.

13542150743 is a deficient number, since it is larger than the sum of its proper divisors (1231104625).

13542150743 is a wasteful number, since it uses less digits than its factorization.

13542150743 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1231104624.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 13542150743 in words is "thirteen billion, five hundred forty-two million, one hundred fifty thousand, seven hundred forty-three".

Divisors: 1 11 1231104613 13542150743