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1354232420311 = 5100472655113
BaseRepresentation
bin10011101101001110100…
…010101101011111010111
311210110111210012212000211
4103231032202231133113
5134141431444422221
62514043100350251
7166561066434061
oct23551642553727
94713453185024
101354232420311
11482365995271
1219a561845387
139a91b984684
144978c050731
15253601506e1
hex13b4e8ad7d7

1354232420311 has 4 divisors (see below), whose sum is σ = 1354235585472. Its totient is φ = 1354229255152.

The previous prime is 1354232420293. The next prime is 1354232420347. The reversal of 1354232420311 is 1130242324531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1354232420311 - 225 = 1354198865879 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1354232420371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 817510 + ... + 1837603.

It is an arithmetic number, because the mean of its divisors is an integer number (338558896368).

Almost surely, 21354232420311 is an apocalyptic number.

1354232420311 is a deficient number, since it is larger than the sum of its proper divisors (3165161).

1354232420311 is an equidigital number, since it uses as much as digits as its factorization.

1354232420311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3165160.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1354232420311 its reverse (1130242324531), we get a palindrome (2484474744842).

The spelling of 1354232420311 in words is "one trillion, three hundred fifty-four billion, two hundred thirty-two million, four hundred twenty thousand, three hundred eleven".

Divisors: 1 510047 2655113 1354232420311