Base | Representation |
---|---|
bin | 10011101101001110100… |
… | …010101101011111010111 |
3 | 11210110111210012212000211 |
4 | 103231032202231133113 |
5 | 134141431444422221 |
6 | 2514043100350251 |
7 | 166561066434061 |
oct | 23551642553727 |
9 | 4713453185024 |
10 | 1354232420311 |
11 | 482365995271 |
12 | 19a561845387 |
13 | 9a91b984684 |
14 | 4978c050731 |
15 | 253601506e1 |
hex | 13b4e8ad7d7 |
1354232420311 has 4 divisors (see below), whose sum is σ = 1354235585472. Its totient is φ = 1354229255152.
The previous prime is 1354232420293. The next prime is 1354232420347. The reversal of 1354232420311 is 1130242324531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1354232420311 - 225 = 1354198865879 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1354232420371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 817510 + ... + 1837603.
It is an arithmetic number, because the mean of its divisors is an integer number (338558896368).
Almost surely, 21354232420311 is an apocalyptic number.
1354232420311 is a deficient number, since it is larger than the sum of its proper divisors (3165161).
1354232420311 is an equidigital number, since it uses as much as digits as its factorization.
1354232420311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3165160.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1354232420311 its reverse (1130242324531), we get a palindrome (2484474744842).
The spelling of 1354232420311 in words is "one trillion, three hundred fifty-four billion, two hundred thirty-two million, four hundred twenty thousand, three hundred eleven".
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