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135423430423303 = 1112553980739341
BaseRepresentation
bin11110110010101010111001…
…011101101111001100000111
3122202111100112201011121112111
4132302222321131233030013
5120222234141142021203
61200004355354001451
740345006564526641
oct3662527135571407
9582440481147474
10135423430423303
113a171832aa0990
1213231b74a16287
135a744b427aa89
142562759839891
15109ca1a69626d
hex7b2ab976f307

135423430423303 has 8 divisors (see below), whose sum is σ = 147746420393616. Its totient is φ = 123102401956800.

The previous prime is 135423430423283. The next prime is 135423430423361. The reversal of 135423430423303 is 303324034324531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135423430423303 - 25 = 135423430423271 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135423430423903) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 490231588 + ... + 490507753.

It is an arithmetic number, because the mean of its divisors is an integer number (18468302549202).

Almost surely, 2135423430423303 is an apocalyptic number.

135423430423303 is a deficient number, since it is larger than the sum of its proper divisors (12322989970313).

135423430423303 is a wasteful number, since it uses less digits than its factorization.

135423430423303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 980751905.

The product of its (nonzero) digits is 933120, while the sum is 40.

Adding to 135423430423303 its reverse (303324034324531), we get a palindrome (438747464747834).

The spelling of 135423430423303 in words is "one hundred thirty-five trillion, four hundred twenty-three billion, four hundred thirty million, four hundred twenty-three thousand, three hundred three".

Divisors: 1 11 12553 138083 980739341 10788132751 12311220947573 135423430423303