Base | Representation |
---|---|
bin | 10011101101001111000… |
… | …101000001010001000111 |
3 | 11210110112102010210100101 |
4 | 103231033011001101013 |
5 | 134141441300223330 |
6 | 2514044021224531 |
7 | 166561236043264 |
oct | 23551705012107 |
9 | 4713472123311 |
10 | 1354241414215 |
11 | 48236aa78548 |
12 | 19a564862147 |
13 | 9a9207b3301 |
14 | 4978d31226b |
15 | 25360d2a4ca |
hex | 13b4f141447 |
1354241414215 has 4 divisors (see below), whose sum is σ = 1625089697064. Its totient is φ = 1083393131368.
The previous prime is 1354241414161. The next prime is 1354241414249. The reversal of 1354241414215 is 5124141424531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1354241414215 - 225 = 1354207859783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135424141417 + ... + 135424141426.
It is an arithmetic number, because the mean of its divisors is an integer number (406272424266).
Almost surely, 21354241414215 is an apocalyptic number.
1354241414215 is a deficient number, since it is larger than the sum of its proper divisors (270848282849).
1354241414215 is an equidigital number, since it uses as much as digits as its factorization.
1354241414215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270848282848.
The product of its digits is 76800, while the sum is 37.
Adding to 1354241414215 its reverse (5124141424531), we get a palindrome (6478382838746).
The spelling of 1354241414215 in words is "one trillion, three hundred fifty-four billion, two hundred forty-one million, four hundred fourteen thousand, two hundred fifteen".
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