135433334531 has 4 divisors (see below), whose sum is σ = 147745455864. Its totient is φ = 123121213200.

The previous prime is 135433334521. The next prime is 135433334557.

135433334531 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135433334531 - 2¹⁰ = 135433333507 is a prime.

It is a super-2 number, since 2×135433334531² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135433334521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6156060650 + ... + 6156060671.

It is an arithmetic number, because the mean of its divisors is an integer number (36936363966).

Almost surely, 2^135433334531 is an apocalyptic number.

135433334531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

135433334531 is a deficient number, since it is larger than the sum of its proper divisors (12312121333).

135433334531 is a wasteful number, since it uses less digits than its factorization.

135433334531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12312121332.

The product of its digits is 291600, while the sum is 38.

It can be divided in two parts, 135433 and 334531, that added together give a palindrome (469964).

The spelling of 135433334531 in words is "one hundred thirty-five billion, four hundred thirty-three million, three hundred thirty-four thousand, five hundred thirty-one".