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13543410331 = 112111929011
BaseRepresentation
bin11001001110100000…
…00000101010011011
31021221212022112022001
430213100000222123
5210214103112311
610115522141431
7656422042213
oct144720005233
937855275261
1013543410331
11581a9a1700
12275b7b1877
13137ab45989
149269c1243
15543ee24c1
hex327400a9b

13543410331 has 6 divisors (see below), whose sum is σ = 14886558596. Its totient is φ = 12312191100.

The previous prime is 13543410323. The next prime is 13543410359. The reversal of 13543410331 is 13301434531.

It is not a de Polignac number, because 13543410331 - 23 = 13543410323 is a prime.

It is a super-2 number, since 2×135434103312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13543410331.

It is not an unprimeable number, because it can be changed into a prime (13543410431) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55964385 + ... + 55964626.

Almost surely, 213543410331 is an apocalyptic number.

13543410331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13543410331 is a deficient number, since it is larger than the sum of its proper divisors (1343148265).

13543410331 is a wasteful number, since it uses less digits than its factorization.

13543410331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111929033 (or 111929022 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 13543410331 its reverse (13301434531), we get a palindrome (26844844862).

The spelling of 13543410331 in words is "thirteen billion, five hundred forty-three million, four hundred ten thousand, three hundred thirty-one".

Divisors: 1 11 121 111929011 1231219121 13543410331