Base | Representation |
---|---|
bin | 11110110010110101001111… |
… | …000100000101000011101010 |
3 | 122202112102012021101102001011 |
4 | 132302311033010011003222 |
5 | 120222424404213322442 |
6 | 1200013433025014134 |
7 | 40345551625304056 |
oct | 3662651704050352 |
9 | 582472167342034 |
10 | 135434530214122 |
11 | 3a176509598027 |
12 | 1323415218434a |
13 | 5a75562a74939 |
14 | 25630cda84c66 |
15 | 109ce69d98117 |
hex | 7b2d4f1050ea |
135434530214122 has 4 divisors (see below), whose sum is σ = 203151795321186. Its totient is φ = 67717265107060.
The previous prime is 135434530214119. The next prime is 135434530214143. The reversal of 135434530214122 is 221412035434531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 85611698570281 + 49822831643841 = 9252659^2 + 7058529^2 .
It is a super-2 number, since 2×1354345302141222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33858632553529 + ... + 33858632553532.
Almost surely, 2135434530214122 is an apocalyptic number.
135434530214122 is a deficient number, since it is larger than the sum of its proper divisors (67717265107064).
135434530214122 is an equidigital number, since it uses as much as digits as its factorization.
135434530214122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67717265107063.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 135434530214122 its reverse (221412035434531), we get a palindrome (356846565648653).
The spelling of 135434530214122 in words is "one hundred thirty-five trillion, four hundred thirty-four billion, five hundred thirty million, two hundred fourteen thousand, one hundred twenty-two".
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