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135437111545 = 527087422309
BaseRepresentation
bin111111000100010101…
…1100101000011111001
3110221120211211010111111
41332020223211003321
54204333400032140
6142115143200321
712533154311341
oct1761053450371
9427524733444
10135437111545
115249079a54a
12222b97460a1
13ca054698b8
1467ab631d21
1537ca35e7ea
hex1f88ae50f9

135437111545 has 4 divisors (see below), whose sum is σ = 162524533860. Its totient is φ = 108349689232.

The previous prime is 135437111533. The next prime is 135437111549. The reversal of 135437111545 is 545111734531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 55520083129 + 79917028416 = 235627^2 + 282696^2 .

It is a cyclic number.

It is not a de Polignac number, because 135437111545 - 211 = 135437109497 is a prime.

It is a super-2 number, since 2×1354371115452 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135437111498 and 135437111507.

It is not an unprimeable number, because it can be changed into a prime (135437111549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13543711150 + ... + 13543711159.

It is an arithmetic number, because the mean of its divisors is an integer number (40631133465).

Almost surely, 2135437111545 is an apocalyptic number.

It is an amenable number.

135437111545 is a deficient number, since it is larger than the sum of its proper divisors (27087422315).

135437111545 is an equidigital number, since it uses as much as digits as its factorization.

135437111545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27087422314.

The product of its digits is 126000, while the sum is 40.

The spelling of 135437111545 in words is "one hundred thirty-five billion, four hundred thirty-seven million, one hundred eleven thousand, five hundred forty-five".

Divisors: 1 5 27087422309 135437111545