Base | Representation |
---|---|
bin | 11110110010111010101111… |
… | …100000000010010111010001 |
3 | 122202112222110100120022100221 |
4 | 132302322233200002113101 |
5 | 120223024011414420103 |
6 | 1200020251451113041 |
7 | 40346151304223650 |
oct | 3662725740022721 |
9 | 582488410508327 |
10 | 135440443123153 |
11 | 3a178a73244103 |
12 | 13235322442781 |
13 | 5a75c95a9988c |
14 | 25634d10a3197 |
15 | 109d1b402b1bd |
hex | 7b2eaf8025d1 |
135440443123153 has 32 divisors (see below), whose sum is σ = 156013732772352. Its totient is φ = 115177744281600.
The previous prime is 135440443123121. The next prime is 135440443123163. The reversal of 135440443123153 is 351321344044531.
It is not a de Polignac number, because 135440443123153 - 25 = 135440443123121 is a prime.
It is a super-2 number, since 2×1354404431231532 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135440443123163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 542281300 + ... + 542531002.
It is an arithmetic number, because the mean of its divisors is an integer number (4875429149136).
Almost surely, 2135440443123153 is an apocalyptic number.
It is an amenable number.
135440443123153 is a deficient number, since it is larger than the sum of its proper divisors (20573289649199).
135440443123153 is a wasteful number, since it uses less digits than its factorization.
135440443123153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251185.
The product of its (nonzero) digits is 1036800, while the sum is 43.
Adding to 135440443123153 its reverse (351321344044531), we get a palindrome (486761787167684).
The spelling of 135440443123153 in words is "one hundred thirty-five trillion, four hundred forty billion, four hundred forty-three million, one hundred twenty-three thousand, one hundred fifty-three".
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