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135441000301135 = 5412232962725589
BaseRepresentation
bin11110110010111011010000…
…101101100000001001001111
3122202120000220011222212212111
4132302323100231200021033
5120223031132034114020
61200020423033244451
740346201151162364
oct3662732055401117
9582500804885774
10135441000301135
113a179229804181
1213235458b63727
135a760543512a9
1425635450a046b
15109d1e7ddad5a
hex7b2ed0b6024f

135441000301135 has 16 divisors (see below), whose sum is σ = 167239934104320. Its totient is φ = 105236012885760.

The previous prime is 135441000301109. The next prime is 135441000301151. The reversal of 135441000301135 is 531103000144531.

It is not a de Polignac number, because 135441000301135 - 213 = 135441000292943 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135441000301097 and 135441000301106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1481317080 + ... + 1481408509.

It is an arithmetic number, because the mean of its divisors is an integer number (10452495881520).

Almost surely, 2135441000301135 is an apocalyptic number.

135441000301135 is a deficient number, since it is larger than the sum of its proper divisors (31798933803185).

135441000301135 is a wasteful number, since it uses less digits than its factorization.

135441000301135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2962725858.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 135441000301135 its reverse (531103000144531), we get a palindrome (666544000445666).

The spelling of 135441000301135 in words is "one hundred thirty-five trillion, four hundred forty-one billion, three hundred one thousand, one hundred thirty-five".

Divisors: 1 5 41 205 223 1115 9143 45715 2962725589 14813627945 121471749149 607358745745 660687806347 3303439031735 27088200060227 135441000301135