Base | Representation |
---|---|
bin | 11110110010111011010000… |
… | …101101100000001001001111 |
3 | 122202120000220011222212212111 |
4 | 132302323100231200021033 |
5 | 120223031132034114020 |
6 | 1200020423033244451 |
7 | 40346201151162364 |
oct | 3662732055401117 |
9 | 582500804885774 |
10 | 135441000301135 |
11 | 3a179229804181 |
12 | 13235458b63727 |
13 | 5a760543512a9 |
14 | 25635450a046b |
15 | 109d1e7ddad5a |
hex | 7b2ed0b6024f |
135441000301135 has 16 divisors (see below), whose sum is σ = 167239934104320. Its totient is φ = 105236012885760.
The previous prime is 135441000301109. The next prime is 135441000301151. The reversal of 135441000301135 is 531103000144531.
It is not a de Polignac number, because 135441000301135 - 213 = 135441000292943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135441000301097 and 135441000301106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1481317080 + ... + 1481408509.
It is an arithmetic number, because the mean of its divisors is an integer number (10452495881520).
Almost surely, 2135441000301135 is an apocalyptic number.
135441000301135 is a deficient number, since it is larger than the sum of its proper divisors (31798933803185).
135441000301135 is a wasteful number, since it uses less digits than its factorization.
135441000301135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2962725858.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 135441000301135 its reverse (531103000144531), we get a palindrome (666544000445666).
The spelling of 135441000301135 in words is "one hundred thirty-five trillion, four hundred forty-one billion, three hundred one thousand, one hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •