Base | Representation |
---|---|
bin | 11110110010111100101011… |
… | …000000001010100111001010 |
3 | 122202120011210202102211101222 |
4 | 132302330223000022213022 |
5 | 120223042232334034424 |
6 | 1200021233225442042 |
7 | 40346253534134324 |
oct | 3662745300124712 |
9 | 582504722384358 |
10 | 135442515143114 |
11 | 3a1799369013a3 |
12 | 13235800340322 |
13 | 5a7623613bcaa |
14 | 256364a348614 |
15 | 109d285db7e5e |
hex | 7b2f2b00a9ca |
135442515143114 has 4 divisors (see below), whose sum is σ = 203163772714674. Its totient is φ = 67721257571556.
The previous prime is 135442515143099. The next prime is 135442515143161. The reversal of 135442515143114 is 411341515244531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 133728293169025 + 1714221974089 = 11564095^2 + 1309283^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33860628785777 + ... + 33860628785780.
Almost surely, 2135442515143114 is an apocalyptic number.
135442515143114 is a deficient number, since it is larger than the sum of its proper divisors (67721257571560).
135442515143114 is an equidigital number, since it uses as much as digits as its factorization.
135442515143114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67721257571559.
The product of its digits is 576000, while the sum is 44.
The spelling of 135442515143114 in words is "one hundred thirty-five trillion, four hundred forty-two billion, five hundred fifteen million, one hundred forty-three thousand, one hundred fourteen".
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