Base | Representation |
---|---|
bin | 11110110010111101100000… |
… | …000000001100110011010011 |
3 | 122202120021002201121221102210 |
4 | 132302331200000030303103 |
5 | 120223101043003011111 |
6 | 1200021501352243203 |
7 | 40346314552206303 |
oct | 3662754000146323 |
9 | 582507081557383 |
10 | 135443404344531 |
11 | 3a17a2528285a8 |
12 | 13235a0a0a0503 |
13 | 5a7634842448a |
14 | 25636d2493603 |
15 | 109d2d8eb00a6 |
hex | 7b2f6000ccd3 |
135443404344531 has 32 divisors (see below), whose sum is σ = 182365726233600. Its totient is φ = 89413331293440.
The previous prime is 135443404344527. The next prime is 135443404344583.
135443404344531 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 135443404344531 - 22 = 135443404344527 is a prime.
It is a super-2 number, since 2×1354434043445312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135443404344511) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 134974815 + ... + 135974583.
It is an arithmetic number, because the mean of its divisors is an integer number (5698928944800).
Almost surely, 2135443404344531 is an apocalyptic number.
135443404344531 is a deficient number, since it is larger than the sum of its proper divisors (46922321889069).
135443404344531 is a wasteful number, since it uses less digits than its factorization.
135443404344531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001019.
The product of its (nonzero) digits is 8294400, while the sum is 48.
It can be divided in two parts, 13544340 and 4344531, that added together give a palindrome (17888871).
The spelling of 135443404344531 in words is "one hundred thirty-five trillion, four hundred forty-three billion, four hundred four million, three hundred forty-four thousand, five hundred thirty-one".
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