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135500433323 = 934931449311
BaseRepresentation
bin111111000110001110…
…1001000011110101011
3110221202020222012122112
41332030131020132223
54210001102331243
6142125324312535
712534553452053
oct1761435103653
9427666865575
10135500433323
115251350a0a2
12223169a274b
13ca1560a7c8
1467b5bd6563
1537d0bbb818
hex1f8c7487ab

135500433323 has 4 divisors (see below), whose sum is σ = 135501976128. Its totient is φ = 135498890520.

The previous prime is 135500433311. The next prime is 135500433353. The reversal of 135500433323 is 323334005531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135500433323 - 210 = 135500432299 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135500433323.

It is not an unprimeable number, because it can be changed into a prime (135500433353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 631163 + ... + 818148.

It is an arithmetic number, because the mean of its divisors is an integer number (33875494032).

Almost surely, 2135500433323 is an apocalyptic number.

135500433323 is a deficient number, since it is larger than the sum of its proper divisors (1542805).

135500433323 is an equidigital number, since it uses as much as digits as its factorization.

135500433323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1542804.

The product of its (nonzero) digits is 48600, while the sum is 32.

Adding to 135500433323 its reverse (323334005531), we get a palindrome (458834438854).

The spelling of 135500433323 in words is "one hundred thirty-five billion, five hundred million, four hundred thirty-three thousand, three hundred twenty-three".

Divisors: 1 93493 1449311 135500433323