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135501222631 = 262103516977
BaseRepresentation
bin111111000110010000…
…0001001001011100111
3110221202022110022101011
41332030200021023213
54210001303111011
6142125353243051
712534563250205
oct1761440111347
9427668408334
10135501222631
11525139a9115
1222317103487
13ca15825b58
1467b5d60075
1537d0cc5621
hex1f8c8092e7

135501222631 has 4 divisors (see below), whose sum is σ = 135502001712. Its totient is φ = 135500443552.

The previous prime is 135501222599. The next prime is 135501222667. The reversal of 135501222631 is 136222105531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 135501222631 - 25 = 135501222599 is a prime.

It is a super-2 number, since 2×1355012226312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135501222593 and 135501222602.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135501222691) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3615 + ... + 520591.

It is an arithmetic number, because the mean of its divisors is an integer number (33875500428).

Almost surely, 2135501222631 is an apocalyptic number.

135501222631 is a deficient number, since it is larger than the sum of its proper divisors (779081).

135501222631 is an equidigital number, since it uses as much as digits as its factorization.

135501222631 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 779080.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 135501222631 in words is "one hundred thirty-five billion, five hundred one million, two hundred twenty-two thousand, six hundred thirty-one".

Divisors: 1 262103 516977 135501222631