Base | Representation |
---|---|
bin | 1100010100101110010000… |
… | …1001000111000011110010 |
3 | 1202222101022120011000220121 |
4 | 3011023210021013003302 |
5 | 3234001204014220132 |
6 | 44452504403400454 |
7 | 2565652313255635 |
oct | 305134411070362 |
9 | 52871276130817 |
10 | 13550154445042 |
11 | 4354651a29076 |
12 | 162a13b38312a |
13 | 773a0a8700b7 |
14 | 34bb8c29dc1c |
15 | 18770d4bb497 |
hex | c52e42470f2 |
13550154445042 has 4 divisors (see below), whose sum is σ = 20325231667566. Its totient is φ = 6775077222520.
The previous prime is 13550154445019. The next prime is 13550154445049. The reversal of 13550154445042 is 24054445105531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13364807835681 + 185346609361 = 3655791^2 + 430519^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13550154445042.
It is not an unprimeable number, because it can be changed into a prime (13550154445049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3387538611259 + ... + 3387538611262.
Almost surely, 213550154445042 is an apocalyptic number.
13550154445042 is a deficient number, since it is larger than the sum of its proper divisors (6775077222524).
13550154445042 is an equidigital number, since it uses as much as digits as its factorization.
13550154445042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6775077222523.
The product of its (nonzero) digits is 960000, while the sum is 43.
The spelling of 13550154445042 in words is "thirteen trillion, five hundred fifty billion, one hundred fifty-four million, four hundred forty-five thousand, forty-two".
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