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13550154445231 = 17797067908543
BaseRepresentation
bin1100010100101110010000…
…1001000111000110101111
31202222101022120011001011121
43011023210021013012233
53234001204014221411
644452504403401411
72565652313256325
oct305134411070657
952871276131147
1013550154445231
114354651a29228
12162a13b383267
13773a0a870201
1434bb8c29dd15
1518770d4bb571
hexc52e42471af

13550154445231 has 4 divisors (see below), whose sum is σ = 14347222353792. Its totient is φ = 12753086536672.

The previous prime is 13550154445229. The next prime is 13550154445253. The reversal of 13550154445231 is 13254445105531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13550154445231 - 21 = 13550154445229 is a prime.

It is a super-2 number, since 2×135501544452312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13559154445231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 398533954255 + ... + 398533954288.

It is an arithmetic number, because the mean of its divisors is an integer number (3586805588448).

Almost surely, 213550154445231 is an apocalyptic number.

13550154445231 is a deficient number, since it is larger than the sum of its proper divisors (797067908561).

13550154445231 is an equidigital number, since it uses as much as digits as its factorization.

13550154445231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 797067908560.

The product of its (nonzero) digits is 720000, while the sum is 43.

The spelling of 13550154445231 in words is "thirteen trillion, five hundred fifty billion, one hundred fifty-four million, four hundred forty-five thousand, two hundred thirty-one".

Divisors: 1 17 797067908543 13550154445231