13550440423 has 4 divisors (see below), whose sum is σ = 14592782008. Its totient is φ = 12508098840.

The previous prime is 13550440391. The next prime is 13550440469. The reversal of 13550440423 is 32404405531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32404405531 = 23 ⋅1408887197.

It is a cyclic number.

It is not a de Polignac number, because 13550440423 - 2⁵ = 13550440391 is a prime.

It is a super-2 number, since 2×13550440423² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13550440723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521170773 + ... + 521170798.

It is an arithmetic number, because the mean of its divisors is an integer number (3648195502).

Almost surely, 2^13550440423 is an apocalyptic number.

13550440423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13550440423 is a deficient number, since it is larger than the sum of its proper divisors (1042341585).

13550440423 is a wasteful number, since it uses less digits than its factorization.

13550440423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1042341584.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 13550440423 its reverse (32404405531), we get a palindrome (45954845954).

The spelling of 13550440423 in words is "thirteen billion, five hundred fifty million, four hundred forty thousand, four hundred twenty-three".