Base | Representation |
---|---|
bin | 10011101101111110111… |
… | …011100100011111010101 |
3 | 11210112121100210201222010 |
4 | 103231332323210133111 |
5 | 134200112311242123 |
6 | 2514255420454433 |
7 | 166620155012220 |
oct | 23557673443725 |
9 | 4715540721863 |
10 | 1355044243413 |
11 | 482742170a53 |
12 | 19a7496aa419 |
13 | 9aa1ac16b83 |
14 | 49827bb65b7 |
15 | 253ab560993 |
hex | 13b7eee47d5 |
1355044243413 has 16 divisors (see below), whose sum is σ = 2065609472000. Its totient is φ = 774018440496.
The previous prime is 1355044243381. The next prime is 1355044243457. The reversal of 1355044243413 is 3143424405531.
It is not a de Polignac number, because 1355044243413 - 25 = 1355044243381 is a prime.
It is a super-2 number, since 2×13550442434132 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355040243413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12132913 + ... + 12244086.
It is an arithmetic number, because the mean of its divisors is an integer number (129100592000).
Almost surely, 21355044243413 is an apocalyptic number.
It is an amenable number.
1355044243413 is a deficient number, since it is larger than the sum of its proper divisors (710565228587).
1355044243413 is a wasteful number, since it uses less digits than its factorization.
1355044243413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24379656.
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 1355044243413 its reverse (3143424405531), we get a palindrome (4498468648944).
The spelling of 1355044243413 in words is "one trillion, three hundred fifty-five billion, forty-four million, two hundred forty-three thousand, four hundred thirteen".
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