Base | Representation |
---|---|
bin | 10011101101111111100… |
… | …010010101001000010011 |
3 | 11210112122001220221211102 |
4 | 103231333202111020103 |
5 | 134200122411412430 |
6 | 2514300422335015 |
7 | 166620340251236 |
oct | 23557742251023 |
9 | 4715561827742 |
10 | 1355054404115 |
11 | 482747980925 |
12 | 19a750b8a46b |
13 | 9aa20063919 |
14 | 4982929d41d |
15 | 253ac3bb345 |
hex | 13b7f895213 |
1355054404115 has 16 divisors (see below), whose sum is σ = 1781085710880. Its totient is φ = 985094315520.
The previous prime is 1355054404073. The next prime is 1355054404157. The reversal of 1355054404115 is 5114044505531.
It is an interprime number because it is at equal distance from previous prime (1355054404073) and next prime (1355054404157).
It is a de Polignac number, because none of the positive numbers 2k-1355054404115 is a prime.
It is a super-2 number, since 2×13550544041152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 274856441 + ... + 274861370.
It is an arithmetic number, because the mean of its divisors is an integer number (111317856930).
Almost surely, 21355054404115 is an apocalyptic number.
1355054404115 is a deficient number, since it is larger than the sum of its proper divisors (426031306765).
1355054404115 is a wasteful number, since it uses less digits than its factorization.
1355054404115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549717862.
The product of its (nonzero) digits is 120000, while the sum is 38.
Adding to 1355054404115 its reverse (5114044505531), we get a palindrome (6469098909646).
The spelling of 1355054404115 in words is "one trillion, three hundred fifty-five billion, fifty-four million, four hundred four thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •