Base | Representation |
---|---|
bin | 10011101101111111100… |
… | …110001101101010101011 |
3 | 11210112122010211200021102 |
4 | 103231333212031222223 |
5 | 134200123142001443 |
6 | 2514300500232015 |
7 | 166620352021214 |
oct | 23557746155253 |
9 | 4715563750242 |
10 | 1355055422123 |
11 | 482748506757 |
12 | 19a75139b60b |
13 | 9aa2032c0b0 |
14 | 4982948640b |
15 | 253ac51ccb8 |
hex | 13b7f98daab |
1355055422123 has 4 divisors (see below), whose sum is σ = 1459290454608. Its totient is φ = 1250820389640.
The previous prime is 1355055422111. The next prime is 1355055422141. The reversal of 1355055422123 is 3212245505531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1355055422123 - 24 = 1355055422107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1355055425123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52117516223 + ... + 52117516248.
It is an arithmetic number, because the mean of its divisors is an integer number (364822613652).
Almost surely, 21355055422123 is an apocalyptic number.
1355055422123 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1355055422123 is a deficient number, since it is larger than the sum of its proper divisors (104235032485).
1355055422123 is a wasteful number, since it uses less digits than its factorization.
1355055422123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104235032484.
The product of its (nonzero) digits is 180000, while the sum is 38.
The spelling of 1355055422123 in words is "one trillion, three hundred fifty-five billion, fifty-five million, four hundred twenty-two thousand, one hundred twenty-three".
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