Base | Representation |
---|---|
bin | 111111000110100111… |
… | …1000001110000101100 |
3 | 110221210011120201121011 |
4 | 1332031033001300230 |
5 | 4210012424404004 |
6 | 142130512515004 |
7 | 12535102566202 |
oct | 1761517016054 |
9 | 427704521534 |
10 | 135513513004 |
11 | 5251a933051 |
12 | 2231b24ba64 |
13 | ca1823a06c |
14 | 67b783d072 |
15 | 37d1e02004 |
hex | 1f8d3c1c2c |
135513513004 has 12 divisors (see below), whose sum is σ = 237182000328. Its totient is φ = 67747227200.
The previous prime is 135513512993. The next prime is 135513513013. The reversal of 135513513004 is 400315315531.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350282 + ... + 2407249.
It is an arithmetic number, because the mean of its divisors is an integer number (19765166694).
Almost surely, 2135513513004 is an apocalyptic number.
It is an amenable number.
135513513004 is a deficient number, since it is larger than the sum of its proper divisors (101668487324).
135513513004 is a wasteful number, since it uses less digits than its factorization.
135513513004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4764656 (or 4764654 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 135513513004 its reverse (400315315531), we get a palindrome (535828828535).
The spelling of 135513513004 in words is "one hundred thirty-five billion, five hundred thirteen million, five hundred thirteen thousand, four".
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