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135515040322 = 267757520161
BaseRepresentation
bin111111000110101010…
…0110110101001000010
3110221210021110022200111
41332031110312221002
54210013322242242
6142131005341534
712535121560054
oct1761524665102
9427707408614
10135515040322
11525207865a2
122231b8678aa
13ca186532bc
1467b7b198d4
1537d2104817
hex1f8d536a42

135515040322 has 4 divisors (see below), whose sum is σ = 203272560486. Its totient is φ = 67757520160.

The previous prime is 135515040281. The next prime is 135515040361. The reversal of 135515040322 is 223040515531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 223040515531 = 1011972204023.

It can be written as a sum of positive squares in only one way, i.e., 134497494121 + 1017546201 = 366739^2 + 31899^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33878760079 + ... + 33878760082.

Almost surely, 2135515040322 is an apocalyptic number.

135515040322 is a deficient number, since it is larger than the sum of its proper divisors (67757520164).

135515040322 is an equidigital number, since it uses as much as digits as its factorization.

135515040322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67757520163.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 135515040322 its reverse (223040515531), we get a palindrome (358555555853).

The spelling of 135515040322 in words is "one hundred thirty-five billion, five hundred fifteen million, forty thousand, three hundred twenty-two".

Divisors: 1 2 67757520161 135515040322