Base | Representation |
---|---|
bin | 10011101110001010011… |
… | …001001001000000010011 |
3 | 11210120002202122122111202 |
4 | 103232022121021000103 |
5 | 134201011023411111 |
6 | 2514330450301415 |
7 | 166625011362662 |
oct | 23561231110023 |
9 | 4716082578452 |
10 | 1355236544531 |
11 | 4828307756a1 |
12 | 19a7a1b8786b |
13 | 9aa4ba06b0c |
14 | 49845552dd9 |
15 | 253bd398b3b |
hex | 13b8a649013 |
1355236544531 has 4 divisors (see below), whose sum is σ = 1401968839200. Its totient is φ = 1308504249864.
The previous prime is 1355236544507. The next prime is 1355236544539. The reversal of 1355236544531 is 1354456325531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1355236544531 is a prime.
It is a super-2 number, since 2×13552365445312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1355236544539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23366147291 + ... + 23366147348.
It is an arithmetic number, because the mean of its divisors is an integer number (350492209800).
Almost surely, 21355236544531 is an apocalyptic number.
1355236544531 is a deficient number, since it is larger than the sum of its proper divisors (46732294669).
1355236544531 is an equidigital number, since it uses as much as digits as its factorization.
1355236544531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46732294668.
The product of its digits is 3240000, while the sum is 47.
The spelling of 1355236544531 in words is "one trillion, three hundred fifty-five billion, two hundred thirty-six million, five hundred forty-four thousand, five hundred thirty-one".
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