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1355262136141 = 7035119264291
BaseRepresentation
bin10011101110001011111…
…010110000111101001101
311210120011112210211121011
4103232023322300331031
5134201034101324031
62514333203005221
7166625442041044
oct23561372607515
94716145724534
101355262136141
11482844164a91
1219a7aa669811
139aa540c7394
1449848ad555b
15253c07516b1
hex13b8beb0f4d

1355262136141 has 4 divisors (see below), whose sum is σ = 1355281470784. Its totient is φ = 1355242801500.

The previous prime is 1355262136133. The next prime is 1355262136177. The reversal of 1355262136141 is 1416312625531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1355262136141 - 23 = 1355262136133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1355262136094 and 1355262136103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1355262136121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9561795 + ... + 9702496.

It is an arithmetic number, because the mean of its divisors is an integer number (338820367696).

Almost surely, 21355262136141 is an apocalyptic number.

It is an amenable number.

1355262136141 is a deficient number, since it is larger than the sum of its proper divisors (19334643).

1355262136141 is an equidigital number, since it uses as much as digits as its factorization.

1355262136141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19334642.

The product of its digits is 129600, while the sum is 40.

The spelling of 1355262136141 in words is "one trillion, three hundred fifty-five billion, two hundred sixty-two million, one hundred thirty-six thousand, one hundred forty-one".

Divisors: 1 70351 19264291 1355262136141