Base | Representation |
---|---|
bin | 1100010100111000110111… |
… | …1111101100000101101111 |
3 | 1202222122200011021121100212 |
4 | 3011032031333230011233 |
5 | 3234023023022230444 |
6 | 44454055241413035 |
7 | 2566113035042465 |
oct | 305161577540557 |
9 | 52878604247325 |
10 | 13553004101999 |
11 | 435588454256a |
12 | 162a7b579a17b |
13 | 77407306554b |
14 | 34bd7c92c835 |
15 | 18782876419e |
hex | c538dfec16f |
13553004101999 has 4 divisors (see below), whose sum is σ = 14142265149936. Its totient is φ = 12963743054064.
The previous prime is 13553004101947. The next prime is 13553004102059. The reversal of 13553004101999 is 99910140035531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13553004101999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13553004104999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294630523934 + ... + 294630523979.
It is an arithmetic number, because the mean of its divisors is an integer number (3535566287484).
Almost surely, 213553004101999 is an apocalyptic number.
13553004101999 is a deficient number, since it is larger than the sum of its proper divisors (589261047937).
13553004101999 is an equidigital number, since it uses as much as digits as its factorization.
13553004101999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 589261047936.
The product of its (nonzero) digits is 656100, while the sum is 50.
The spelling of 13553004101999 in words is "thirteen trillion, five hundred fifty-three billion, four million, one hundred one thousand, nine hundred ninety-nine".
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