Base | Representation |
---|---|
bin | 11110110100001110100111… |
… | …111011000011101101010011 |
3 | 122202212120221021212001121000 |
4 | 132310032213323003231103 |
5 | 120231012441114131120 |
6 | 1200125505031233043 |
7 | 40355520250504212 |
oct | 3664164773035523 |
9 | 582776837761530 |
10 | 135530510302035 |
11 | 3a203191879732 |
12 | 1324a879818783 |
13 | 5a8161a7b0574 |
14 | 25679d6c8b079 |
15 | 10a06d6227990 |
hex | 7b43a7ec3b53 |
135530510302035 has 64 divisors (see below), whose sum is σ = 242280813640320. Its totient is φ = 71881655040000.
The previous prime is 135530510302013. The next prime is 135530510302069. The reversal of 135530510302035 is 530203015035531.
135530510302035 is a `hidden beast` number, since 1 + 3 + 5 + 5 + 305 + 10 + 302 + 0 + 35 = 666.
It is not a de Polignac number, because 135530510302035 - 217 = 135530510170963 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1797425335 + ... + 1797500735.
It is an arithmetic number, because the mean of its divisors is an integer number (3785637713130).
Almost surely, 2135530510302035 is an apocalyptic number.
135530510302035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135530510302035 is a deficient number, since it is larger than the sum of its proper divisors (106750303338285).
135530510302035 is a wasteful number, since it uses less digits than its factorization.
135530510302035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149157 (or 149151 counting only the distinct ones).
The product of its (nonzero) digits is 101250, while the sum is 36.
Adding to 135530510302035 its reverse (530203015035531), we get a palindrome (665733525337566).
The spelling of 135530510302035 in words is "one hundred thirty-five trillion, five hundred thirty billion, five hundred ten million, three hundred two thousand, thirty-five".
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