Base | Representation |
---|---|
bin | 111111000111001101… |
… | …0111001000000111001 |
3 | 110221211120000002121001 |
4 | 1332032122321000321 |
5 | 4210033022300441 |
6 | 142132503045001 |
7 | 12535433615140 |
oct | 1761632710071 |
9 | 427746002531 |
10 | 135533400121 |
11 | 52530086589 |
12 | 22325a40761 |
13 | ca1c3b0ca2 |
14 | 67ba338757 |
15 | 37d3a2e731 |
hex | 1f8e6b9039 |
135533400121 has 8 divisors (see below), whose sum is σ = 161629893504. Its totient is φ = 111120551520.
The previous prime is 135533400113. The next prime is 135533400127. The reversal of 135533400121 is 121004335531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 135533400121 - 23 = 135533400113 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 135533400121.
It is not an unprimeable number, because it can be changed into a prime (135533400127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 420911020 + ... + 420911341.
It is an arithmetic number, because the mean of its divisors is an integer number (20203736688).
Almost surely, 2135533400121 is an apocalyptic number.
It is an amenable number.
135533400121 is a deficient number, since it is larger than the sum of its proper divisors (26096493383).
135533400121 is an equidigital number, since it uses as much as digits as its factorization.
135533400121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 841822391.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 135533400121 its reverse (121004335531), we get a palindrome (256537735652).
The spelling of 135533400121 in words is "one hundred thirty-five billion, five hundred thirty-three million, four hundred thousand, one hundred twenty-one".
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