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135534404033 = 788069219851
BaseRepresentation
bin111111000111001111…
…0101110000111000001
3110221211121220002200222
41332032132232013001
54210033301412113
6142132540352425
712535445266040
oct1761636560701
9427747802628
10135534404033
1152530701866
1222326245715
13ca1c672c12
1467ba51a557
1537d3b7be08
hex1f8e7ae1c1

135534404033 has 8 divisors (see below), whose sum is σ = 154898925120. Its totient is φ = 116170498800.

The previous prime is 135534404029. The next prime is 135534404039. The reversal of 135534404033 is 330404435531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135534404033 - 22 = 135534404029 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135534403984 and 135534404002.

It is not an unprimeable number, because it can be changed into a prime (135534404039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 506558 + ... + 726408.

It is an arithmetic number, because the mean of its divisors is an integer number (19362365640).

Almost surely, 2135534404033 is an apocalyptic number.

It is an amenable number.

135534404033 is a deficient number, since it is larger than the sum of its proper divisors (19364521087).

135534404033 is an equidigital number, since it uses as much as digits as its factorization.

135534404033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 307927.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 135534404033 its reverse (330404435531), we get a palindrome (465938839564).

The spelling of 135534404033 in words is "one hundred thirty-five billion, five hundred thirty-four million, four hundred four thousand, thirty-three".

Divisors: 1 7 88069 219851 616483 1538957 19362057719 135534404033