Base | Representation |
---|---|
bin | 111111000111001111… |
… | …0101110000111000111 |
3 | 110221211121220002201012 |
4 | 1332032132232013013 |
5 | 4210033301412124 |
6 | 142132540352435 |
7 | 12535445266046 |
oct | 1761636560707 |
9 | 427747802635 |
10 | 135534404039 |
11 | 52530701871 |
12 | 2232624571b |
13 | ca1c672c18 |
14 | 67ba51a55d |
15 | 37d3b7be0e |
hex | 1f8e7ae1c7 |
135534404039 has 2 divisors, whose sum is σ = 135534404040. Its totient is φ = 135534404038.
The previous prime is 135534404029. The next prime is 135534404069. The reversal of 135534404039 is 930404435531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135534404039 - 24 = 135534404023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135534403987 and 135534404005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135534404029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767202019 + 67767202020.
It is an arithmetic number, because the mean of its divisors is an integer number (67767202020).
Almost surely, 2135534404039 is an apocalyptic number.
135534404039 is a deficient number, since it is larger than the sum of its proper divisors (1).
135534404039 is an equidigital number, since it uses as much as digits as its factorization.
135534404039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 135534404039 in words is "one hundred thirty-five billion, five hundred thirty-four million, four hundred four thousand, thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •