Base | Representation |
---|---|
bin | 11001001111110100… |
… | …10111010010010001 |
3 | 1021222122012121100112 |
4 | 30213322113102101 |
5 | 210224423404131 |
6 | 10121000131105 |
7 | 656615313506 |
oct | 144772272221 |
9 | 37878177315 |
10 | 13554513041 |
11 | 58261952a3 |
12 | 2763466a95 |
13 | 1380232424 |
14 | 9282714ad |
15 | 544e8702b |
hex | 327e97491 |
13554513041 has 4 divisors (see below), whose sum is σ = 13558549284. Its totient is φ = 13550476800.
The previous prime is 13554513017. The next prime is 13554513043. The reversal of 13554513041 is 14031545531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5543547025 + 8010966016 = 74455^2 + 89504^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13554513041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13554512989 and 13554513007.
It is not an unprimeable number, because it can be changed into a prime (13554513043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2013080 + ... + 2019801.
It is an arithmetic number, because the mean of its divisors is an integer number (3389637321).
Almost surely, 213554513041 is an apocalyptic number.
It is an amenable number.
13554513041 is a deficient number, since it is larger than the sum of its proper divisors (4036243).
13554513041 is an equidigital number, since it uses as much as digits as its factorization.
13554513041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4036242.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 13554513041 in words is "thirteen billion, five hundred fifty-four million, five hundred thirteen thousand, forty-one".
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