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13555040501531 = 30725234411697
BaseRepresentation
bin1100010101000000011101…
…0111111011111100011011
31202222211221002010102100202
43011100013113323330123
53234041210332022111
644455033304452415
72566214353125404
oct305200727737433
952884832112322
1013555040501531
114356729a90691
12162b08377a10b
13774308c15699
1434c0d31809ab
151878e7416b3b
hexc54075fbf1b

13555040501531 has 4 divisors (see below), whose sum is σ = 13555047985752. Its totient is φ = 13555033017312.

The previous prime is 13555040501507. The next prime is 13555040501573. The reversal of 13555040501531 is 13510504055531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13555040501531 is a prime.

It is a super-2 number, since 2×135550405015312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13555040501501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 866675 + ... + 5278371.

It is an arithmetic number, because the mean of its divisors is an integer number (3388761996438).

Almost surely, 213555040501531 is an apocalyptic number.

13555040501531 is a deficient number, since it is larger than the sum of its proper divisors (7484221).

13555040501531 is an equidigital number, since it uses as much as digits as its factorization.

13555040501531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7484220.

The product of its (nonzero) digits is 112500, while the sum is 38.

The spelling of 13555040501531 in words is "thirteen trillion, five hundred fifty-five billion, forty million, five hundred one thousand, five hundred thirty-one".

Divisors: 1 3072523 4411697 13555040501531