13555040502001 has 4 divisors (see below), whose sum is σ = 13558685313600. Its totient is φ = 13551395690404.

The previous prime is 13555040501993. The next prime is 13555040502011. The reversal of 13555040502001 is 10020504055531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13555040502001 - 2³ = 13555040501993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13555040502011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1822400221 + ... + 1822407658.

It is an arithmetic number, because the mean of its divisors is an integer number (3389671328400).

Almost surely, 2^{13555040502001} is an apocalyptic number.

It is an amenable number.

13555040502001 is a deficient number, since it is larger than the sum of its proper divisors (3644811599).

13555040502001 is an equidigital number, since it uses as much as digits as its factorization.

13555040502001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3644811598.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 13555040502001 its reverse (10020504055531), we get a palindrome (23575544557532).

The spelling of 13555040502001 in words is "thirteen trillion, five hundred fifty-five billion, forty million, five hundred two thousand, one".