Search a number
-
+
13555040501993 is a prime number
BaseRepresentation
bin1100010101000000011101…
…0111111100000011101001
31202222211221002010102222212
43011100013113330003221
53234041210332030433
644455033304454505
72566214353126634
oct305200727740351
952884832112885
1013555040501993
114356729a90a71
12162b08377a435
13774308c15963
1434c0d3180c1b
151878e7416d48
hexc54075fc0e9

13555040501993 has 2 divisors, whose sum is σ = 13555040501994. Its totient is φ = 13555040501992.

The previous prime is 13555040501971. The next prime is 13555040502011. The reversal of 13555040501993 is 39910504055531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12764349634729 + 790690867264 = 3572723^2 + 889208^2 .

It is an emirp because it is prime and its reverse (39910504055531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13555040501993 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13555040501953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6777520250996 + 6777520250997.

It is an arithmetic number, because the mean of its divisors is an integer number (6777520250997).

Almost surely, 213555040501993 is an apocalyptic number.

It is an amenable number.

13555040501993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13555040501993 is an equidigital number, since it uses as much as digits as its factorization.

13555040501993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1822500, while the sum is 50.

The spelling of 13555040501993 in words is "thirteen trillion, five hundred fifty-five billion, forty million, five hundred one thousand, nine hundred ninety-three".