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13555244103403 = 15838563009541
BaseRepresentation
bin1100010101000001001110…
…0000100111011011101011
31202222212110021020110121211
43011100103200213123223
53234042114442302103
644455105420413551
72566222404534022
oct305202340473353
952885407213554
1013555244103403
114356823a037a2
12162b11b9a72b7
1377433c161272
1434c11221d8b9
1518790a23336d
hexc54138276eb

13555244103403 has 4 divisors (see below), whose sum is σ = 13563807114528. Its totient is φ = 13546681092280.

The previous prime is 13555244103341. The next prime is 13555244103407. The reversal of 13555244103403 is 30430144255531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13555244103403 - 217 = 13555243972331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13555244103407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4281503188 + ... + 4281506353.

It is an arithmetic number, because the mean of its divisors is an integer number (3390951778632).

Almost surely, 213555244103403 is an apocalyptic number.

13555244103403 is a deficient number, since it is larger than the sum of its proper divisors (8563011125).

13555244103403 is an equidigital number, since it uses as much as digits as its factorization.

13555244103403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8563011124.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 13555244103403 its reverse (30430144255531), we get a palindrome (43985388358934).

The spelling of 13555244103403 in words is "thirteen trillion, five hundred fifty-five billion, two hundred forty-four million, one hundred three thousand, four hundred three".

Divisors: 1 1583 8563009541 13555244103403